本篇文章是对Oracle查询和删除JOB的SQL的实现方法进行了详细的分析介绍，需要的朋友参考下
查询及删除重复记录的SQL语句1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断select * from people
where peopleId in (selectpeopleId frompeople group bypeopleId having count(peopleId) > 1)2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录delete from people
where peopleId in (selectpeopleId from people group bypeopleIdhaving count(peopleId) > 1)and rowid not in (select min(rowid) frompeople group by peopleId having count(peopleId )>1)
注:rowid为oracle自带不用该.....3、查找表中多余的重复记录（多个字段） select * from vitae a
where (a.peopleId,a.seq) in(select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录delete from vitae a
where (a.peopleId,a.seq) in(select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录select * from vitae a
where (a.peopleId,a.seq) in(select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)(二)比方说
在A表中存在一个字段“name”，
而且不同记录之间的“name”值有可能会相同，
现在就是需要查询出在该表中的各记录之间，“name”值存在重复的项；
Select Name,Count(*) from A Group By Name Having Count(*) > 1
如果还查性别也相同大则如下:
Select Name,sex,Count(*) from A Group By Name,sex Having Count(*) > 1(三)方法一declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >； 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch ......
